keakon的涂鸦馆

>>> a = 1 if 2 == 3 else 4
>>> a
4
>>> isLeapYear = lambda year: not (year % 4 if year % 100 else year % 400) # 判断闰年
>>> isLeapYear(1234)
False
>>> isLeapYear(1236)
True
>>> isLeapYear(1000)
False
>>> isLeapYear(2000)
True
>>> [i + 1 if i % 2 for i in xrange(10)] # 不能省略else
  File "<stdin>", line 1
    [i + 1 if i % 2 for i in xrange(10)]
                      ^
SyntaxError: invalid syntax
>>> [i + 1 if i % 2 else i for i in xrange(10)]
[0, 2, 2, 4, 4, 6, 6, 8, 8, 10]
>>> [i % 2 and i + 1 or  i for i in xrange(10)] # 之前的语法
[0, 2, 2, 4, 4, 6, 6, 8, 8, 10]